A ball was kicked from the ground into the air with an initial upward velocity of 32 feet per second.Write an equation to model the height of the ball and find the maximum height that it reached.

Question

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Answer 1

Height h=32t-16t² where t is time and acceleration due to gravity is 32 ft/sec² acting against the velocity of the ball kicked into the air. This equation can be rewritten: h=16(2t-t²)=16(1-1+2t-t²)=16-(1-t)². When t=1 the ball reaches maximum height of 16 ft, because nothing is subtracted from 16, whereas all other values of t reduce 16.