prove LHS to RHS not RHS to LHS , and pls keep it simple
in Trigonometry Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

Check the supposed identity by substituting a value for x. Let x=30°, then sin(2x)=√3/2, tan(x)=1/√3. The RHS becomes:

(2/√3)/(1+⅓)=(2/√3)/(4/3)=(2/√3)(3/4)=√3/2, so the identity appears to be true.

sin(2x)=2sin(x)cos(x)=

2(sin(x)/cos(x))cos2(x)=

2tan(x)/sec2(x)=

2tan(x)/(1+tan2(x)) QED

[sin2(x)+cos2(x)=1, so, dividing through by cos2(x):

tan2(x)+1=sec2(x)]

by Top Rated User (1.1m points)

Related questions

2 answers
1 answer
1 answer
1 answer
1 answer
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,545 questions
99,733 answers
2,417 comments
486,008 users