x^2 - 16x = 80

solve for x
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1 Answer

x^2 - 16x -80 =0

x^2 -20x +4x -80 =0

x(x-20) + 4(x-20) =0

(x-20)(x+4) =0

So either (x-20)=0 or (x+4)=0

so, x = 20 or x=-4

 

by Level 8 User (30.1k points)

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