There are 5 green, 3 yellow,and 2 red marbles in a ag. what is the probability of getting 3 green marbles with out replacing them?
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There are 5+3+2=10 marbles in the bag, 5 of which are green, so the probability of the first marble being green is 5/10=½.

That leaves 9 marbles in the bag (because the green is not replaced), 4 of which are green, so the probability of the second marble being green is 4/9, and there are 8 remaining marbles, 3 of which are green.

The probability of the third marble being green is ⅜.

Combine these probabilities: 1/2×4/9×3/8=1/12.

ago by Top Rated User (1.1m points)

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