What is (1+i)^(1-i)?

Question

i = √-1, the  imaginary square root of negative 1. I think I have the answer but I would like confirmation.

Answer 1

sqrt(2) * e^ (pi/4) { cos(pi/4 - ln(sqrt(2)))  + i sin(pi/4 - ln (sqrt(2))}

or 2.8 + 1.32 i

Full solution:

https://ibb.co/wSgF5LN

 

Comments

Thanks. I was counting on you solving it. It does in fact simplify further by expanding the sin and cos. This removes the √2 at the beginning. And it does confirm my solution.

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Thank You, Sir.