How to proove without using substitution?
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Let C₁=35n+n²/2=n(35+n), and C₂=2n(35+2n).

C₂/C₁=2n(35+2n)/(n(35+n))=2(35+2n)/(35+n).

35+2n=35+n+n, divided by 35+n is 1+n/(35+n).

So C₂/C₁=2+2n/(35+n).

Therefore C₂ is not twice C₁ (unless n was zero). If n=-35, C₂ is infinitely more than C₁.

by Top Rated User (1.1m points)

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