Find the derivative y=(2x-4)^5(2-x^3)^2

Find the derivative y=(2x-4)^5(2-x^3)^2
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y=(2x-4)^5(2-x^3)^2

y' = d(2x-4)^5 *(2-x^3)^2 +(2x-4)^5d(2-x^3)^2

y'=5(2x-4)^4*2*(2-x^3)^2 +(2x-4)^5*2(2-x^3)*(-3x^2

y'=(2x-4)^4*2*(2-x^3){5(2-x^3)+(2x-4)(-3x^2)}

y'=2(2x-4)^4*(2-x^3){5(2-x^3) -3x^2(2x-4)}
by Level 8 User (36.8k points)

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