How do I make "t" the subject of the equation Square root of (3- pi(t))/ 2a - 1 = 4(square root of 2).

"a" does not equal a half

t < 3/pi
in Algebra 1 Answers by

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1 Answer

t = (-128 a^2 + 128 a - 29)/pi
by Level 8 User (30.1k points)

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