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in Algebra 1 Answers by Level 1 User (400 points)

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When -3x2-x+24<0, its square root is complex, so 3x2+x-24>0, (3x-8)(x+3)>0, so 3x-8>0 and x+3>0; or 3x-8<0 and x+3<0.

Therefore, the square root is complex when x>8/3 or x<-3.

by Top Rated User (1.1m points)

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