(20b^3+17b^2+22b+49) / (4b+5)

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1 Answer

Algebraic long division:

             5b² -2b   +8          

4b+5 ) 20b³+17b²+22b+49

           20b³+25b²

                     -8b²+22b

                     -8b²-10b

                             32b+49

                             32b+40

                                       9

Answer: 5b²-2b+8 remainder 9. If 49 had been 40, there would have been no remainder.

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