I want to know if this function is harmonic or not
in order of operations by

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1 Answer

Let u=sin(3x)y3,

∂u/∂x=3cos(3x)y3,

∂u/∂y=3sin(3x)y2,

2u/∂x2=-9sin(3x)y3,

2u/∂y2=6sin(3x)y.

Laplace equation:

2u=Δu=∂2u/∂x2+∂2u/∂y2≡0 for harmonic functions.

In this case, ∂2u/∂x2+∂2u/∂y2=-9sin(3x)y3+6sin(3x)y=3ysin(3x)(2-3y2)≢0, so the given function is not harmonic.

by Top Rated User (1.1m points)

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