The length of a new rectangular playing field is 9 yards longer than quadruple the width. If the perimeter of the rectangular playing field is 538 ​yards, what are its​ dimensions?

The length of a new rectangular playing field is 9 yards longer than quadruple the width. If the perimeter of the rectangular playing field is 538 ​yards, what are its​ dimensions?

the Width is ? yards.
in Algebra 2 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

If w is the width then the length is 4w+9.

The perimeter is 2(length+width)=2(w+4w+9)=538,

5w+9=538/2=269,

5w=260,

w=52yd, so length=4×52+9=208+9=217yd.

Dimensions are 52yd by 217yd.
by Top Rated User (1.1m points)

Related questions

Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!

Most popular questions within the last 3000 days

  1. 50+50-25X0+2+2= (19)
  2. it takes 10 road workers 5 days to complete a road repair when working 2 hours a day.Working at the same pace,how many days will it take 2 people working 5 hours a day to finish it? (3)
  3. complete the following. 825 use each digit once .make the two smallest 3 digit numbers and two largest 3-digit number (2)
  4. Solve 15 -1(12÷4+1)? (4)
  5. 8:4(5+2) (3)

Most popular tags

87,542 questions
99,804 answers
2,417 comments
523,119 users