(Q5) General exponential equation P(t)=P0ekt where P0 is the initial population when t=0, where t is the number of hours and k is a constant. P is the population after time t hours.
P0=200000. When t=1 (hour), the A population doubles, so PA(1)=400000=200000ek, ek=2, k=ln(2), so PA(t)=200000etln(2).
PA(t)=200000(2t) because tln(2)=ln(2t).
(Q6) PB(t)=50000(4t), because after an hour PB doubles twice and 22=4. This can also be written:
PB(t)=50000(22t). (When t=½, PB(½)=100000; 4t=4½=√4=2; 22t=21=2.)
(Q7) Inequality is PB>PA, that is: 50000(22t)>200000(2t), 22t>4(2t), 22t>22(2t), 22t>2t+2, 2t>t+2, t>2 is the inequality, meaning that (Q8) t is more than 2 hours. (Example: t=2½ hours: PB=1,600,000; PA=1,131,370.)

PA is shown in red while PB is in blue. The green line represents t=2.5 hours. The blue curve is higher than the red when t>2 hours.