3a^2-13a-10/5+4a-a^2

Question

I need to reduse these fractions to simplest forms. I have reduced the numerator to (a-5)(3a+2) but am having trouble with the denominator. I know I have to put it in standard form but I am not doing something right. Thank you

Answer 1

3a^2-13a-10/5+4a-a^2

=(a-5)(3a+2)/-(a^2-4a-5)   here take the -ve sign outside  and proceed

=(a-5)(3a+2)/-(a-5)(a+1)

=3a+2/-(a+1)

=-(3a+2)/(a+1)

Hope you got it now.