find -10÷(-2) using repeated subtraction.

find -10÷(-2) using repeated subtraction.
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2 Answers

me dont no nuthun bout "repeeted subtrakt",

but 10/2=5, however yu look at it
by
[-10]-1]-{-1}=[a+b}+c+[cb]-a

so that would mean that [-10]=[-1]x[-1]10x's

then you add [-1]x[-1]10x+[a+b}+c+[cb]-a=42
by

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