solve this problem ((x+y)/(x^2-y^2)) * ((x^2-2xy+y^2)/(x^2-xy))

simplify comepletely
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1 Answer

(x+y)/(x2-y2)=1/(x-y); x2-2xy+y2=(x-y)2; x2-xy=x(x-y)

Therefore: (x+y)/(x2-y2) × (x2-2xy+y2)/(x2-xy)=1/x

by Top Rated User (1.1m points)

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