how do you use the law of cosines to solve a triangle with two sides given and one angle.

the triangle has side ac 25 and cb 25 and angle c being 140 degrees. Find x- side ab
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1 Answer

ab = sqrt[(ac)^2 + (bc)^2 - 2(ac)(bc)cos(c)]
ab = sqrt[25^2 + 25^2 - 2(25)(25)cos(140)]
ab = 46.98463104
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