Question

find 3 consecutive integers such that twice the least integer is 12 more than the greatest integer

Answer 1

2*a=(a+2)+12

2*a=a+14

a=14

Answer 2

The small of two integers is 5 less than twice the larger. The product of the two integers is equal to 3. Find both integers.

Answer 3

Problem: find 3 consecutive integers such that twice the least integer is 12 more than the greatest integer
find 3 consecutive integers such that twice the least integer is 12 more than the greatest integer

x, x + 1, x + 2

2x = (x + 2) + 12
2x = x + 14
x = 14

14, 15, 16

2 * 14 = 16 + 12
28 = 28