Equation of tangent line

Question

 Find the equation of the tangent line to the graph of the given function at the point with the indicated x-coordinate.

f(x) = x + (1/x);  x = 3

y = ?

 

Answer 1

y=x+(1/x) ...want tangent...thats the derivativ

dy/dx=1 + (-1*x^-2)

at x=3, dy/dx=1 -3^-2

=1- (1/9)

=1-0.11111111...

make that 8/9=0.8888888