Each side of the pyramid is divided into two right triangles with base = 3/2 and hypotenuse of slant height. The height of the triangle is foung using the pythagorean theorem:
7^2 = 1^2 + h^2
49 - 1 = 48 = h^2
h = 6.93cm
Area of each triangle:
A = 1/2(b)(h)
A = 1/2(1)(6.93) = 3.46cm^2
There are 12 of these triangles in the surface of the pyramid:
12(3.46) = 41.6cm^2 = Surface Area
If you wish to find the area of the base:
A = (3SQR3/2)s^2 where s = side length
A ~ 2.598(2 ^2) = 10.4cm^2 = Base Area