the slope of a straight line -3/4 and p is a given point

the slope of a straight line -3/4 and p is a given point
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Let us suppose the given point p is (X,Y). The general equation of the line is y=mx+c where m is the slope and c the y intercept. m=-3/4, so y=-3x/4+c. To find c we plug in the (x,y) values for p: Y=-3X/4+c, so c=Y+3X/4. The equation of the line is y=-3x/4+Y+3X/4=Y+(3/4)(X-x). Example: if p is (1,2), X=1 and Y=2, so y=2+(3/4)(1-x)=2+3/4-3x/4=(11-3x)/4 or 4y=11-3x.

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