2x+4y+z=-1, 5x-2y-z=-9, 3x+y+2z=-14

Elimination method
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Call the equations A, B and C. A + B gives 7x + 2y = -10. Call this equation D. 2B + C = 13x - 3y = -32. Call this equation E. 3D + 2E = 47x = -94, so x = -2. Substitute this value in equation D or E and we get y = 2. Substitute these values of x and y in A, B or C and we get z = -5.

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2x+y-z=7 x-2y+2z=-9 3x-y+z=5
asked Dec 11, 2013 in Algebra 2 Answers by anonymous | 1.4k views
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