how do you solve cos 3x=3x ?

How would you go about solving this problem? Steps would be much appreciated! Thanks.
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1 Answer

Let f(x)=cos(3x)-3x.= f'(x)=-3sin(3x)-3.

Newton's Method (iterative):

xn+1=x-f(xn)/f'(xn).

Let x0=0, then x1=⅓, x2=0.2501..., x3=0.2463..., ... x=0.246361711072 after a few iterations.

by Top Rated User (1.1m points)

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