how do i factor 9x^3+18x^2-4x-8

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1 Answer

9x3+18x2-4x-8=9x2(x+2)-4(x+2)=(9x2-4)(x+2) (x+2 is a common factor).

This further factorises: (3x-2)(3x+2)(x+2).

by Top Rated User (1.1m points)

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