D=5e^(-.9h) given that D=4

Question

D=5e^(-0.9h) can be used to find the number of milligrams D of a certain drug in a patient's bloodstream h hours after the drug has been administered. When the number of milligrams reaches 4, the drug is to be administered again. What is the time between injections?

Answer 1

5e^(-0.9 ours)=4

or e^(-0.9 t) =0.8

ln(0.8)=-0.9t

t= ln(0.8) / (-0.9)

ln(0.8)=-0.223143551

so t=+(9.223143551)/0.9

t=0.2479 ours=14.876 minuts or bout 15 min

Answer 2

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Answer 3

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Answer 4

help me in this .Given that f(20) = 24, f(24) = 32, f(28)=35, f(32) = 40, find f(25) using Gauss forward interpolation formula.

Answer 5

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