Evaluate:

S= Integrate sign

 

S  t^2 cos (1-t ^3) dt
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1 Answer

∫t2(cos(1-t3)dt.

Let x=1-t3, then dx=-3t2dt, so t2dt=-dx/3 and cos(1-t3)=cos(x).

∫t2(cos(1-t3)dt=-⅓∫cos(x)dx=-⅓sin(x)+C, where C is an integration constant.

Replacing x: C-⅓sin(1-t3) is the indefinite integral.

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