alright, to isolate r we'll have to use inverse operations
here is your original equation to refer back to: 2000[1 + r(51/365)] = 2038.11
first, let's divide both sides by 2000, so we'll have 1.02 (roughly - i rounded up)
now the equation is 1 + r(51/365) = 1.02
subtract 1 from both sides
now we have approximately .02
51/365 is roughly equal to .14
with our equation set up as r(51/365) = .02, we'll divide both sides by 51/365
now we have, as a very long decimal, .1363740196, which we can round to .14 or, if you want, .136
r = .136
now we'll go back and check the work
2000[1 + .136(51/365)] = 2038.11
multiply .136 with 51/365 first, in accordance with the order of operations, to get .019
now add 1 to get 1.019
now multiply this by 2000
the answer comes out to 2038.11
so r is approximately equal to 0.136