find derivatives of

p=(2t+3)^3/4t^2-1

 

r=(5t-6)^4/3t^2+4
in Calculus Answers by Level 1 User (120 points)

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1 Answer

  1. dy/dx=5(2x³+9x)⁴(6x²+9)
  2. ds/dt=(18√(2t⁴+5))(8t³)=144t³√(2t⁴+5)
  3. Assume p=(2t+3)³/(4t²-1), dp/dt=((4t²-1)(3(2t+3)²(2)-(2t+3)³(8t))/(4t²-1)² = 6(2t+3)²/(4t²-1)-8t(2t+3)³/(4t²-1)²
  4. Assume r=(5t-6)⁴/(3t²+4), dr/dt=20(5t-6)³/(3t²+4)-6t(5t-6)⁴/(3t²+4)²

 

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