how do you calculate the hight of a right angle triangle with only only the base?

Question

how to calculate thehight of a right angle triangle with only the base and all other angles??

Answer 1

Given the base and the angles:

The angle touching the base (not the right angle)- call that "theta." (since I don't know how to make that Pokeball-looking angle symbol here)

tan(theta) = height / base

(see here:  http://zonalandeducation.com/mmts/trigonometryRealms/introduction/rightTriangle/trigRightTriangle.html )

height = base * tan(theta)

Answer 2

me assume 90deg at left end av the base

At rite end, yu hav angel, sae 30 deg...then hite/base=tan(30 deg)=0.5773502691896257

so hite=base*0.57735...

base/diagonal=kosine(30)=0.8660254037844386

so diagonal=base/0.86602540...