what are the double roots of x^2(x^4+16)=8x^4
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1 Answer

x2(x4+16)=8x4,

x2(x4+16)-8x4=0,

x2(x4+16-8x2)=x2(x2-4)2=x2(x-2)2(x+2)2=0.

So x=0 is a double root, as are x=2 and x=-2.

ago by Top Rated User (1.1m points)

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