h(x)=x^3+5x^2-4x-20

Could you find all the zeros of this polynomial function?
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1 Answer

h(x)=x^3-4x+5x^2-20=x(x^2-4)+5(x^2-4)=(x+5)(x^2-4)=(x+5)(x-2)(x+2), so zeroes are at x=-5,2,-2.
by Top Rated User (1.1m points)

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