(6^(-1)a^(7)b^(6))/(3^(-3)a^(8)b^(-6))

I need help solving this equation.  This is a fraction

 

6-1a7b6

3-3a8b-6

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1 Answer

6-1=⅙; 1/3-3=33=27; a7/a8=1/a8-7=1/a; b6/b-6=b6+6=b12.

So we have (27/6)(1/a)b12=(9/2)b12/a=4.5b12/a.

ago by Top Rated User (1.1m points)

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