A line passes through the points (-8, 7) and (x2, y2), and has a slope of -3/14. If point (x2, y2) is located in quadrant I, find x2.

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1 Answer

The slope is (y2 - y1) / (x2 - x1) = -3 / 14

(y2 - 7) = -3    and   (x2 - (-8)) = 14

y2 = -3 + 7 = 4        x2 + 8 = 14 = 14 - 8 = 6

x2 = 6   <<<<<
by Level 11 User (78.4k points)

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