it takes 1 hour long to fly to st. paul at 200 mi/h than it does to return at 250 mi/h. how far away is st. paul?
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find three consecutive integers whose sum is 126

it takes 1 hour long to fly to st. paul at 200 mi/h than it does to return at 250 mi/h. how far away is st. paul?

I am sorry your quistion is mix up.

For the Second quistion

time travel going with the win resistance Tg = 1 hour

rate to travel with the win = 200 mph

Win resistance  = Wres in mph

Wres + 200 = 250

Wres = 250 - 200

Wrs = 50 mph

Disatance  from starting point to St. Paul = (Velosity in going - Wres) / Tg

Disatance  from starting point to St. Paul = (200 - 50) / Tg

Disatance  from starting point to St. Paul = (150) / 1

 

Disatance  from starting point to St. Paul = 150 miles ◄ Ans

by Level 3 User (2.7k points)

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