How to solve 8x^2+6x+5=0 using the quadratic formula?

Question

I am struggling with this and I feel hopeless.. what are the two solutions? Thanks a ton.

Answer 1

Quadratic Formula: -b <plus or minus> <square root of> b^2-4ac <over> 2a

A=8; B=6; C=5

[-(6) +/- <square root of> (6)^2-4(8)(5)] / 2(6)

[-6 +/- <square root of> 36-160] / 12

[-6 +/- <square root of> -124] / 12

[-6 +/- i<square root of> 124] / 12

NOTE: square root of 124 divide by square root of 4 (which is 2) = square root of 31 which can not be further simplified

ANSWER: [-6 +/- 2i <square root of> 31] / 12     {OR}     -1/2 +/- 1/6i <square root of> 31