Solve for "n" if nP6=5nP5. "P" means permutations

Solve for "n" if nP6 = 5nP5
in order of operations by

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1 Answer

nP6=n(n-1)(n-2)(n-3)(n-4)(n-5); nP5=n(n-1)(n-2)(n-3)(n-4), so nP6=(n-5)nP5.

(n-5)nP5=5nP5. Cancel out nP5: n-5=5, so n=10.

by Top Rated User (1.1m points)

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