given f(x)=4x^2+2x determine the points where the curve intercepts the x axis

f(x)=4x^2+2x curve intercepts x axis
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1 Answer

at (0,0)&(-1/2,0)

Solution:-

 due to curve is touching X-axis ,at that points y=0

=>4x^2+2x=0

=>x(4x+2)=0

therefore,x=0 or x=-1/2

so at x=0 and at x=-1/2 the curve touches the x-axis

so the curve intersects the x-axis at the points (0,0),(-1/2,0)

 

 

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