How do i use the quadratic formula for 2x^2+16x+32=0
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1 Answer

2x^2 + 16x + 32=0

it's simply find discriminant

d=b^2-4ac for (ax^2+bx+c=0)

d=(16)^2 -4(2)(32)=256-256=0

hence roots will be real and equal

x=(-b+d^(1/2))/2a

x=(-16+0)/4

x=-4

hence both root are -4,-4

graph will touch x axis at (-4,0) only and always above x axis
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