the length of a rectangle 5 yds more than twice its width and the area of the rectangle is 42yds^2. Find the dimensions of the rectangle.
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4 Answers

What would be a good word problem for this quadratic equation: x2-6x+8
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The length of a rectangle is 3 ft less than twice it's width and the area of the rectangle is 44 ft^2 find the dimensions of the rectangle.
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I think the answer of the Dimension of the rectangle is -6 x3.5

 

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If a numbr added to five is divided by the difference of the number and two, the result is three-fourths. Find the number
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