In Diagram show PQR is a triangle and QRS is a quadrant of circle with centre Q .. The arc RS is 55 cm . Calculate the area of whole diagram .
in Calculus Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

arc RS=55cm so circumference of the circle=4×55=220cm=2πr, where r=radius.

r=220/(2π)=110/π cm.

Since we have no other information or dimensions (we need the height and base lengths of the triangle), we could assume PQR is equilateral, because PQR cannot be inside the quadrant else we would only need the area of the sector which is independent of the area of the triangle. (It could also be an isosceles right triangle with QR as the height or hypotenuse.) We'll just consider the equilateral triangle.

Area of equilateral triangle=¼s2√3. s=r, so the combined areas are:

¼πr2+¼r2√3=¼r2(π+√3) where r=110/π.

(π+√3)/4=1.2184 approx, so the area is 1.2184r2=1493.76cm2 approx.

by Top Rated User (1.1m points)

Related questions

2 answers
asked Sep 8, 2012 in Calculus Answers by anonymous | 925 views
0 answers
1 answer
asked Dec 12, 2014 in Algebra 1 Answers by pbuford | 702 views
2 answers
1 answer
1 answer
asked Feb 17, 2014 in Geometry Answers by Anonymous | 1.1k views
1 answer
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,542 questions
99,771 answers
2,417 comments
505,410 users