find the ellipse 1

Question

 for x^2 /169 + y^2 /144+1
find
a. length of semi major axis
b. " " " minor axis
c. coordinates of the foci
d. eccentricity

Answer 1

(1)

a) a=√169=13

b) b=√144=12 (+1 should be =1)

c) focal distance from centre (0,0) is √(169-144)=√25=5. Foci at (-5,0) and (5,0).

d) √(1-144/169)=√(25/169)=5/13.