solve 3x=-18+4y 16y=58+5x using elimination
Help me please!!!!!!!!!!!!
Re-arrange both of these equations.
3x = -18 + 4y 16y = 58 + 5x
3x - 4y = -18 -5x + 16y = 58
Multiply the equationon the left by 4, so that both
equations have the same coefficient for y.
4 * (3x - 4y) = -18 * 4
12x - 16y = -72
Add the equations.
12x - 16y = -72
+(-5x + 16y = 58)
-------------------------
7x = -14
Solve that equation.
7x = -14
x = -2
Substitute that value into one of the
original equations to find the value of y.
-5x + 16y = 58
-5(-2) + 16y = 58
10 + 16y = 58
16y = 48
y = 3
Of course, you should use both values in the other equation
to verify your answer.
3x = -18 + 4y
3(-2) = -18 + 4(3)
-6 = -18 + 12
-6 = -6
Done.
x = -2 and y = 3