Use chain rule to find the following derivative:

((t-3)^2) / ((t+1)^1/2)
in Calculus Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

f(t) = (t - 3)^2 / (t + 1)^1/2 = g(t) / h(t)

Using chain rule for quotients which is

f'(t) = g'(t) * h(t) - g(t) * h'(t) / h(t)^2

we get

f'(t) = [2*(t - 3)*(t +1)^1/2 - (t - 3)^2*(1/2*(t + 1)^-1/2)] / (t + 1)

done!
by Level 2 User (1.7k points)

Related questions

1 answer
1 answer
asked Apr 8, 2020 in Calculus Answers by qwertykl Level 2 User (1.4k points) | 1.6k views
1 answer
asked Sep 20, 2013 in Calculus Answers by anonymous | 1.2k views
1 answer
1 answer
asked May 22, 2013 in Calculus Answers by anonymous | 622 views
1 answer
1 answer
asked Oct 15, 2012 in Calculus Answers by anonymous | 1.8k views
1 answer
1 answer
1 answer
asked Feb 20, 2020 in Calculus Answers by anonymous | 725 views
1 answer
asked Feb 19, 2020 in Calculus Answers by anonymous | 394 views
1 answer
asked Nov 8, 2012 in Calculus Answers by anonymous | 673 views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,544 questions
99,732 answers
2,417 comments
484,517 users