how can Ievalute ∫ [1,18]sqrt(3/z)dz?

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I=∫√(3/z)dz

Let x2=3z, 2xdx=3dz, dz=⅔xdx; z=x2/3, √(3/z)=√(9/x2)=3/x.

When z=1, x=√3; z=18, x=√54=3√6.

I=⅔∫[√3,3√6]3dx=⅔[3x]√33√6=⅔(9√6-3√3)=6√6-2√3.

by Top Rated User (1.1m points)

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