Proof of ʃ sec x dx = ln | sec x + tan x | + C with the way to solve it

Proof of ʃ sec x dx = ln | sec x + tan x | + C with the way to solve it. Please help me to know the way to proof it
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If we differentiate ln|sec(x)+tan(x)|+C we should get the integrand. Chain Rule:

(1/(sec(x)+tan(x))(sec(x)tan(x)+sec2(x))=(1/(sec(x)+tan(x))sec(x)(tan(x)+sec(x))=sec(x).

This proves that ∫sec(x)dx=ln|sec(x)+tan(x)|+C.

by Top Rated User (1.1m points)

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