dy/dx = y / 1-e^x
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2 Answers

O man i hate derivatives but this looks like you have to use quotent rule.

y/1-e^x=  f'(x)g(g)-f(x)g'(gx)/g(x)^2 (derivative of y is just y prime or y' and derivative of e^x is just e^x times derivative of x which is just 1) (for example e^x^2 would just be e^x^2 x 2x)

y'(1-e^x)-y(1-e^x) / (1-e^x)^2  is your answer
by Level 6 User (15.3k points)
dy/dx +y = 1/ (1 + e^x )
by

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