X^2-12x+32=0

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anonymous · Answer 1 · 2013-04-04T00:13:41+0000

Answer : ( x -8 ) (x -4)

Work;

(x) (x)= x^2

(x) (-4)= -4x

(-8) (x)= -8x

(-8) (-4)= 32

Put the results together x^2-4x-8x+32

add -4x+-8x = 12x

then; x^2-12x+32=0