(pi)^x=e^(x+3); xln(pi)=x+3; x(ln(pi)-1)=3; x=3/(ln(pi)-1)=3/ln((pi)/e).
log-(x+1)=log(5x/x)=log(5); -(x+1)=5; x+1=-5, so x=-6. Note that only log(-x-1) can be evaluated in the initial expression, because log(5x)=log(-30) and log(x)=log(-6) cannot be evaluated even though log(5x/x) can.