x^2+12+11x+5+13x-17=180

Determine the longest side if a triangle
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1 Answer

x²+24x-180=0=(x-6)(x+30).

Assume x²+12, 11x+5 and 13x-17 are the angles of the triangle.

Put x=6 to find the angles: 48, 71 and 61 degrees.

The longest side is opposite the largest angle, so it’s the side facing angle 71 degrees.

by Top Rated User (1.1m points)

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