(3xy^-2)^2/(x^3)^2

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1 Answer

(3xy-2)2=9x2y-4; (x3)2=x6, 1/x6=x-6, so:

(3xy-2)2/(x3)2=9x2-6y-4=9x-4y-4=9(xy)-4=9/(xy)4.

by Top Rated User (1.1m points)

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